How to calculate the cubic capacity of round timber: the main methods. Seminar “Efficient pellet production” Table measuring round timber 11 meters long

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For industrial procurement round timber It is quite difficult to determine its cubic capacity. To accurately calculate the volume of each log, you can use the formula for the volume of a truncated cone, which takes into account the main diameters of both cuts and the length of the log itself.

Round timber is very convenient and practical for building houses, bathhouses and other residential and non-residential premises.

In fact, like this in a complicated way The cubic size of round timber is not calculated. It is accepted all over the world to be considered more in a fast way. Special tables are used for this.

How to calculate the cubic capacity of a single tree without additional measurements?

Just a few years ago, to calculate the volume of a single tree, they used the product of the arithmetic average of the area of ​​the cuts and the length of the tree. Using a meter (reminiscent of an ordinary caliper), the diameter of the tree in its middle part was determined. Then it was multiplied by 3 to obtain the cross-sectional area.

Next, the resulting number was multiplied by the length of the workpiece, and a volumetric result was obtained. This method of calculation is inaccurate, since the thickness of the bark is not taken into account. The number Pi was taken with a large deviation from the real one, and the formula in its distorted form gave large errors.

The formula itself looks like this: the diameter of a rounded log is divided by 2 and squared, then multiplied by Pi and the length of the log.

Even if you measure the thickness of the bark and take this into account to determine the diameter of the tree, deviations from real indicators will be inaccurate, although with a smaller error. More accurate calculations showed that actual deviations in cubic capacity calculations round log with primitive measurements they have a certain dependence on the parameters of the tree, which was taken into account when compiling the corresponding tables to determine the volumetric parameter. Let's try to figure out how to calculate the cubic capacity of the forest. For this you will need:

  • roulette;
  • corresponding calculation tables, where there is a finite cubic capacity.

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?
Peculiarities .
How much does a cube of board weigh?

Technology for calculating the volume of a single log

First, you need to use a tape measure to measure the length of the tree and its diameter at the top of the cut (excluding the bark). After this, let’s look at the tabular parameters: at the intersection of the line indicating the length of the tree and the column indicating the corresponding diameter, we find the volume of the measured body. Everything is simple and reliable.

Such calculations also cannot be called absolutely accurate, since the features in which the forest was grown and the shape of the trunk are not taken into account. But with large volumes of workpieces, it is customary not to pay attention to such trifles.

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Calculation of cubic capacity of stored timber

For industrial volumes of round logs, other techniques and tabular data are used. In essence, a round forest in a stored state has the shape of a rectangular parallelepiped. Calculations of its volume are familiar to everyone from school. But this method cannot be used, since the size of the voids between the logs will not be taken into account. By the way, they also directly depend on the diameter of the logs, which can be calculated mathematically.

Through numerous calculations, a coefficient was determined, with the help of which a special table was compiled. It works similarly to the previously described table, with the only difference being that the volume of the mentioned parallelepiped and average thickness of the upper cut. The cubic capacity of the forest can be calculated with great accuracy.

But one cannot hope for good accuracy of calculations when stacking forest products inaccurately. This procedure is not used when warehouse storage timber, since in this case the volume occupied by round timber directly in the warehouse is estimated.

It is very easy to calculate the cubic capacity after preliminary weighing of the forest.

Next, you need to calculate the volume by dividing the mass of the forest by the density, which corresponds to the type of wood. This calculation also cannot be considered ideal, since the forest has a deviation in density at different degrees of maturity. The moisture content of the wood can also play a special role here.

When implementing construction work for the construction of a residential building, a specialist must perform big number various tasks, one of which is: drawing up and calculating the estimated cost to the final finishing of the premises of a residential building. It is mandatory to calculate the required amount of various building materials, which is quite difficult to do. Therefore, such knowledge - how many boards are in a cube - has a very important for a specialist who is engaged in the construction of a residential building and wants to complete the work as efficiently and quickly as possible.

Buying club: existing types of boards

To calculate exactly how many board pieces are in a cube, you will need to know not only what exactly a board cube means, but it is worth understanding important point that exist different kinds boards and what is possible to purchase on modern market for performing various construction works. It should be noted that the cube of almost all materials, regardless of the type of material, is calculated in the same way, that is, according to one specific method. The types of boards have no influence on the calculation of the cubic capacity of this building material.

Non-grooved types of lumber are: timber, various edged boards, as well as unedged boards (they are an exception when calculating cubic capacity, because this process occurs a little differently). Tongue-and-groove types (which have special grooves for making joints) include: modern lining, blockhouse, flooring material, as well as imitation natural timber. When you choose a tongue-and-groove type of building material to purchase, then you will need to pay attention to the fact that when making calculations, only working width boards without tenons. If we talk about a blockhouse (imitation log), then when calculating the cubic capacity, only the thickness at its highest point is taken.

How many boards are in 1 cube: performing the calculation

Any person, even from his school days, understands how cubic capacity is calculated. For this procedure, it is necessary to calculate quantities such as: length, width and height. A similar principle is used to calculate the cubic capacity of 1 board. When performing such calculations, it is recommended to convert all available values ​​into meters. The cubic capacity of 1 board, which has a cross-section of 150x20 mm. and a length of 6 m, is calculated as follows: 0.15 multiplied by 0.02 and 6, so that the cubic capacity of this board will be 0.018 cubic meters.

Let's apply the volume formula V= L*h*b (where L is length, h is height, b is width).

L= 6.0; h= 0.02; b= 0.15.

Thus, V= 6.0*0.02*0.15 = 0.018 m3.

To determine how many boards are in one cube: divide 1 m3 by cubic capacity (the volume of one board).

1 m 3 / V = ​​N pcs.

1 m 3 / 0.018 m 3 = 55.55 pcs.

Thus, the number of boards in one cube is 55.5 pieces.

Finding out the cost of a certain type of board when the values ​​of its volume is known is quite easy: 0.018 multiplied by the price of 1 cubic meter. When 1 cube of a certain type of board costs, for example, 5,500 rubles, then the cost will be 99 rubles. At this point in the calculation, there is some trick of sellers and managers in construction stores, because the cubic capacity of the material is rounded to some integer values.

Such rounding can lead to such a moment that the price of 1 board (when 1 cube costs 5500) will be completely different values. In addition to all this, it should be noted that various boards for construction, which have a nominal length of 6 meters, the actual length is 6.1 - 6.2 m, which is not taken into account when selling this building material. This also applies to the purchase significant number boards This can be seen quite clearly if we use a 150x20 mm board as an example. The number of boards in a cube is a value of 55.5 pcs. But, in a cube they count 55 pieces, which when performing the calculation will have a value of 0.99 cubic meters. In fact, it follows from this that the overpayment for 1 cubic meter of this popular building material can amount to 1% of the real price. For example, 5500 instead of 4995 rubles.

To calculate the cubic capacity for a continuous type of board, slightly different methods are used. When we are talking about buying 1 board, then measuring its thickness, as well as the total length, is carried out in the same way as when choosing edged building material. In this case, the average width is taken for calculations - between great value and small.

For example, when the width of the board at one end is 25 cm, and at the other 20, then the average value will be approximately 22 centimeters. When it is necessary to calculate the volume of a significant number of similar boards for construction, then you will need to lay them out so that the wide one does not differ from the narrow one, more than 10 cm. The main length of this material in the laid out stack should be approximately the same. After this, using a regular tape measure, an accurate measurement is made of the height of the entire existing stack of boards, and the width is measured (approximately in the very middle). The result obtained will then need to be multiplied by a special coefficient, amounting to a value from 0.07 to 0.09, directly dependent on the existing air gap.

How many boards are in 1 cube: special tables

To calculate the exact number of boards of a certain width and length in 1 cubic meter, various tables are used. Below are several such specialized tables, which indicate the cubic capacity of the common and in demand types of this material today. It is possible to calculate the volume of various boards of different sizes, for example, material for erecting a fence on your site, using the existing formula presented above.

Table of the amount of edged boards in 1 cubic meter

Board size Volume of 1st board (m 3) Number of boards in 1m 3 (pcs.) Number of square meters in 1m2
Twenty
Board 20x100x6000 0.012 m 3 83 pcs. 50 m2
Board 20x120x6000 0.0144 m 3 69 pcs. 50 m2
Board 20x150x6000 0.018 m 3 55 pcs. 50 m2
Board 20x180x6000 0.0216 m 3 46 pcs. 50 m2
Board 20x200x6000 0.024 m 3 41 pcs. 50 m2
Board 20x250x6000 0.03 m 3 33 pcs. 50 m2
Twenty-five
Board 25x100x6000 0.015 m 3 67 pcs. 40 m2
Board 25x120x6000 0.018 m 3 55 pcs. 40 m2
Board 25x150x6000 0.0225 m 3 44 pcs. 40 m2
Board 25x180x6000 0.027 m 3 37 pcs. 40 m2
Board 25x200x6000 0.03 m 3 33 pcs. 40 m2
Board 25x250x6000 0.0375 m 3 26 pcs. 40 m2
Thirty
Board 30x100x6000 0.018 m 3 55 pcs. 33 m2
Board 30x120x6000 0.0216 m 3 46 pcs. 33 m2
Board 30x150x6000 0.027 m 3 37 pcs. 33 m2
Board 30x180x6000 0.0324 m 3 30 pcs. 33 m2
Board 30x200x6000 0.036 m 3 27 pcs. 33 m2
Board 30x250x6000 0.045 m 3 22 pcs. 33 m2
Thirty-two
Board 32x100x6000 0.0192 m 3 52 pcs. 31 m2
Board 32x120x6000 0.023 m 3 43 pcs. 31 m2
Board 32x150x6000 0.0288 m3 34 pcs. 31 m2
Board 32x180x6000 0.0346 m 3 28 pcs. 31 m2
Board 32x200x6000 0.0384 m 3 26 pcs. 31 m2
Board 32x250x6000 0.048 m 3 20 pcs. 31 m2
Sorokovka
Board 40x100x6000 0.024 m 3 41 pcs. 25 m2
Board 40x120x6000 0.0288 m3 34 pcs. 25 m2
Board 40x150x6000 0.036 m 3 27 pcs. 25 m2
Board 40x180x6000 0.0432 m 3 23 pcs. 25 m2
Board 40x200x6000 0.048 m 3 20 pcs. 25 m2
Board 40x250x6000 0.06 m 3 16 pcs. 25 m2
Fifty
Board 50x100x6000 0.03 m 3 33 pcs. 20 m2
Board 50x120x6000 0.036 m 3 27 pcs. 20 m2
Board 50x150x6000 0.045 m 3 22 pcs. 20 m2
Board 50x180x6000 0.054 m 3 18 pcs. 20 m2
Board 50x200x6000 0.06 m 3 16 pcs. 20 m2
Board 50x250x6000 0.075 m 3 13 pcs. 20 m2

Table of the amount of timber in 1 cubic meter

Beam size Volume of 1st piece (m³) Quantity of timber in 1m³ (pcs.)
100×100×6000 0.06 m 3 16 pcs.
100×150×6000 0.09 m 3 11 pcs.
150×150×6000 0.135 m 3 7 pcs.
100×180×6000 0.108 m 3 9 pcs.
150×180×6000 0.162 m 3 6 pcs.
180×180×6000 0.1944 m 3 5 pieces.
100×200×6000 0.12 m 3 8 pcs.
150×200×6000 0.18 m 3 5.5 pcs.
180×200×6000 0.216 m 3 4.5 pcs.
200×200×6000 0.24 m 3 4 things.
250×200×6000 0.3 m 3 3 pcs.

Table of the amount of unedged boards in 1 cubic meter

This question is the most pressing when it comes to building a house from a log. How to calculate the cubic capacity of a house yourself? How to check the declared forest cubes in the estimate from the developer?

Here is a table showing the cubic capacity of round timber depending on the diameter of the log. These calculations are presented in accordance with GOST 2708-75, which has been in force in the Russian Federation since 1975. The table allows you to calculate how many cubes of round timber will be needed to build a house from logs from the manufacturer.

Standard length of logs used for the construction of log houses is 6 meters. Blanks of this length are most often used. Logs longer than 6 meters are used to make houses manual cutting very rarely.

Most often, the architect optimizes the log house according to the cutting map in such a way as to avoid (or minimize) the use of long lengths. It is technically impossible to produce a rounded log over 6 meters.
Below in the table you can see a block of round timber, and for your convenience, we have highlighted a column of 6-meter blanks.

Table for calculating the cubic capacity of round timber with a diameter of 10 to 100 cm and a length of 3 to 8 meters

3.5 m 4 m 4.5 m 5 m 5.5 m 6 m 6.5 m 7 m 7.5 m 8 m
0,026 0,031 0,037 0,044 0,051 0,058 0,065 0,075 0,082 0,09 0,1
D 11 cm 0,032 0,037 0,045 0,053 0,062 0,07 0,08 0,09 0,098 0,108 0,12
D 12 cm 0,038 0,046 0,053 0,063 0,073 0,083 0,093 0,103 0,114 0,125 0,138
D 13 cm 0,045 0,053 0,062 0,075 0,085 0,097 0,108 0,12 0,132 0,144 0,158
D 14 cm 0,052 0,061 0,073 0,084 0,097 0,11 0,123 0,135 0,15 0,164 0,179
D 15 cm 0,06 0,071 0,084 0,097 0,11 0,125 0,139 0,153 0,169 0,182 0,199
D 16 cm 0,069 0,082 0,095 0,11 0,124 0,14 0,155 0,172 0,189 0,2 0,22
D 17 cm 0,077 0,092 0,107 0,124 0,14 0,157 0,174 0,191 0,209 0,225 0,25
D 18 cm 0,086 0,103 0,12 0,138 0,156 0,175 0,194 0,21 0,23 0,25 0,28
D 19 cm 0,097 0,115 0,134 0,154 0,173 0,193 0,212 0,235 0,255 0,275 0,305
3.0 m 3.5 m 4.0 m 4.5 m 5.0 m 5.5 m 6.0 m 6.5 m 7.0 m 7.5 m 8.0 m
D 20 cm 0,107 0,126 0,147 0,17 0,19 0,21 0,23 0,26 0,28 0,3 0,33
D 21 cm 0,119 0,14 0,163 0,185 0,21 0,23 0,255 0,285 0,31 0,335 0,365
D 22 cm 0,134 0,154 0,178 0,2 0,23 0,25 0,28 0,31 0,34 0,37 0,4
D 23 cm 0,114 0,169 0,194 0,22 0,25 0,275 0,305 0,335 0,37 0,4 0,435
D 24 cm 0,157 0,184 0,21 0,24 0,27 0,3 0,33 0,36 0,4 0,43 0,47
D 25 cm 0,171 0,197 0,23 0,26 0,295 0,325 0,36 0,395 0,43 0,465 0,505
D 26 cm 0,185 0,21 0,25 0,28 0,32 0,35 0,39 0,43 0,46 0,5 0,54
D 27 cm 0,203 0,23 0,27 0,305 0,345 0,38 0,42 0,46 0,495 0,54 0,585
D 28 cm 0,22 0,25 0,29 0,33 0,37 0,41 0,45 0,49 0,53 0,58 0,63
D 29 cm 0,235 0,27 0,31 0,355 0,395 0,44 0,485 0,525 0,57 0,62 0,675
3m 3.5 m 4 m 4.5 m 5 m 5.5 m 6 m 6.5 m 7 m 7.5 m 8 m
D 30 cm 0,25 0,29 0,33 0,38 0,42 0,47 0,52 0,56 0,61 0,66 0,72
D 31 mm
0,265 0,31 0,355 0,405 0,45 0,5 0,555 0,6 0,655 0,72 0,77
D 32 cm 0,28 0,33 0,38 0,43 0,48 0,53 0,59 0,64 0,7 0,76 0,82
D 33 cm 0,3 0,35 0,405 0,46 0,51 0,565 0,625 0,68 0,74 0,805 0,87
D 34 cm 0,32 0,37 0,43 0,49 0,54 0,6 0,66 0,72 0,78 0,85 0,92
D 35 cm 0,34
 0,395 0,455 0,515 0,57 0,635 0,7 0,76 0,83 0,9
 0,97
D 36 cm 0,36 0,42 0,48 0,54 0,6 0,67 0,74
 0,8 0,88 0,95 1,02
0,375
 0,44 0,505 0,57 0,635 0,705 0,78 0,85 0,925 1,0 1,075
D 38 cm 0,39
 0,46 0,53 0,6 0,67 0,74 0,82 0,9 0,97
 1,05 1,13
D 39 cm 0,41
 0,48 0,555 0,63 0,705 0,78 0,86 0,945 1,02 1,105 1,19
3m3.5 m4 m4.5 m5 m5.5 m6 m6.5 m7 m7.5 m8 m
0,43
 0,5 0,58 0,66 0,74 0,82 0,9 0,99 1,07 1,16 1,25
D 41 cm 0,45 0,53 0,61 0,695 0,775 0,86 0,95 1,035 1,125 1,22 1,315
D 42 cm 0,47
 0,56 0,64 0,73 0,81 0,9 1,0 1,08 1,18 1,28 1,38
D 43 cm 0,495
 0,585 0,67 0,765 0,85 0,945 1,045 1,14 1,24 1,34 1,34
D 44 cm 0,515
 0,61 0,7 0,8 0,89 0,89 1,09 1,2
 1,3
 1,4 1,51
D 45 cm 0,543
 0,64 0,735 0,835 0,935 1,035 1,14 1,25 1,355 1,465 1,48
D 46 cm 0,57
 0,67 0,77 0,87 0,98 1,08 1,19 1,3 1,41 1,53 1,65
D 47 cm 0,595
 0,7 0,805 0,91 1,02 1,13 1,245 1,355 1,475 1,6 1,725
D 48 cm 0,62
 0,73 0,84 0,95 1,06 1,18 1,3 1,41 1,54 1,167 1,8
D 49 cm 0,645
 0,76
 0,875 0,99 1,105 1,23 1,355 1,475 1,605 1,74 1,875
3m3.5 m4 m4.5 m5 m5.5 m6 m6.5 m7 m7.5 m8 m
D 50 cm 0,67
 0,79 0,91 1,03 1,15 1,28 1,41 1,54 1,67 1,81 1,95
D 51 cm 0,7
 0,825 0,95 1,075 1,2 1,335
 1,47 1,605 1,74 1,89 2,035
D 52 cm 0,73
 0,86 0,99 1,12 1,25 1,39 1,53 1,67 1,81 1,97 2,12
D 53 cm 0,765
 0,895 1,03 1,165
 1,3 1,445 1,59 1,735 1,885 2,045 2,205
D 54 cm 0,8
 0,93 1,07 1,21 1,35 1,5 1,65 1,8 1,96 2,12 2,29
D 55 cm 0,83
 0,97 1,115 1,26 1,405 1,56 1,715 1,875 2,035 2,2 2,375
D 56 cm 0,86
 1,01 1,16 1,31 1,46 1,62 1,78 1,95 2,11 2,28 2,46
D 57 cm 0,89
 1,045 1,205 1,36 1,515 1,68 1,875 2,015 2,19 2,365 2,545
D 58 cm 0,92
 1,08 1,25 1,41 1,57 1,74 1,91 2,08 2,27 2,45 2,63
D 59 cm 0,955
 1,12 1,29 1,46 1,625 1,8 1,98 2,155 2,345 2,535 2,72
3m3.5 m4 m4.5 m5 m5.5 m6 m6.5 m7 m7.5 m8 m
D 60 cm 0,99
 1,16 1,33 1,151 1,151 1,86 2,05 2,23 2,42 2,62 2,81
D 61 cm 1,025
 1,2 1,38 1,565 1,74 1,925 2,115 2,3 2,495 2,7 2,9
D 62 cm 1,06 1,24 1,43 1,62 1,8 1,99 2,18 2,37 2,57 2,78 2,99
D 63 cm 1,095
 1,285 1,475 1,67 1,855 2,05 2,25 2,445 2,65 2,865 3,08
D 64 cm 1,13
 1,33 1,52 1,72 1,61 2,11 2,32 2,52 2,73 2,95 3,17
D 65 cm 1,165
 1,365 1,565 1,77 1,965 2,17 2,38 2,59 2,805 3,03 3,275
D 66 cm 1,2
 1,4 1,61 1,82 2,02 2,23 2,44 2,66 2,88 3,11 3,38
D 67 cm 1,235
 1,445 1,655 1,87 2,075 2,29 2,505 2,735 2,965 3,21 3,485
D 68 cm 1,27
 1,49 1,7 1,92 2,13 2,35 2,57 2,81 3,05 3,31 3,59
D 69 cm 1,305
 1,53 1,75 1,97 2,19 2,415 2,645 2,89 3,14 3,41 3,695
3m3.5 m4 m4.5 m5 m5.5 m6 m6.5 m7 m7.5 m8 m
D 70 cm 1,34
 1,57 1,8 2,02 2,25 2,48 2,72 2,97 3,23 3,51 3,8
D 71 cm 1,375
 1,615 1,85 2,08 2,315 2,55 2,795 3,055 3,325 3,615 3,91
D 72 cm 1,41
 1,66 1,9 2,14 2,38 2,62 2,87 3,14 3,42 3,72 4,02
D 73 cm 1,45
 1,705 1,955 2,2 2,45 2,695 2,95
 3,23 3,52 3,82 4,135
D 74 cm 1,49
 1,75 2,01 2,26 2,52 2,77 3,03 3,32 3,62 3,92 4,25
D 75 cm 1,53
 1,8 2,065 2,325 2,595 2,845 3,115 3,415 3,715
 4,03 4,365
D 76 cm 1,57
 1,85 2,12 2,39 2,67 2,92 3,2 3,51 3,81 4,14 4,48
D 77 cm 1,615
 1,9 2,18 2,455 2,745 3,0 3,29 3,605 3,925 4,255 4,6
D 78 cm 1,66
 1,95 2,24 2,52 2,82 3,08 3,38 3,7 4,04 4,37 4,72
D 79 cm 1,7
 2,0 2,295 2,59 2,895 3,16 3,475 3,8 4,15 4,485 4,835
3m3.5 m4 m4.5 m5 m5.5 m6 m6.5 m7 m7.5 m8 m
D 80 cm 1,74
 2,05 2,35 2,66 2,97 3,24 3,57 3,9 4,26 4,6 4,95
D 81 cm 1,785
 2,1 2,41 2,73 3,05 3,325 3,66 4,005 4,365 4,51 5,085
D 82 cm 1,83
 2,15 2,47 2,8 3,13 3,41 3,75 4,11 4,47 4,82 5,22
D 83 cm 1,875
 2,205 2,53 2,87 3,205 3,495 3,845 4,215 4,585 4,495 5,345
D 84 cm 1,92 2,26 2,59 2,94 3,28 3,58 3,94 4,32 4,7 5,07 5,47
D 85 cm 1,965
 2,315 2,65 2,985 3,34 3,675 4,035 4,43 4,82 5,195 5,595
D 86 cm 2,01
 2,37 2,71 3,03 3,4 3,77 4,13 4,54 4,94 5,32 5,72
D 87 cm 2,06
 2,425 2,78 3,13 3,5 3,86 4,235 4,655 5,06 5,445 5,86
D 88 cm 2,11
 2,48 2,85 3,23 3,6 3,95 4,34 4,77 5,18 5,57 6,0
D 89 cm 2,16
 2,535 2,915 3,3 3,685 4,045 4,45 4,88 5,3 5,7 6,135
3m3.5 m4 m4.5 m5 m5.5 m6 m6.5 m7 m7.5 m8 m
D 90 cm 2,21
 2,59 2,98 3,37 3,77 4,145 4,56 4,99 5,42 5,83 6,27
D 91 cm 2,255
 2,65 3,045 3,45 3,45 4,24 4,67 5,105 5,545 5,96 6,41
D 92 cm 2,3
 2,71 3,11 3,53 3,94 4,34 4,78
 5,22 5,67 6,09 6,55
D 93 cm 2,355
 2,77 3,18 3,605 4,025 4,43 4,89 5,345 5,795 6,225 6,69
D 94 cm 2,41
 2,83
 3,25 3,68 4,11 4,52 5,0 5,47 5,92 6,36 6,83
D 95 cm 2,46 2,89 3,32 3,76 4,2 4,625 5,11 5,58 6,045 6,495 6,975
D 96 cm 2,51
 2,95 3,39 3,84 4,29 4,73 5,22 5,69 6,17 6,63 7,12
D 97 cm 2,565
 3,01 3,46 3,92 4,38 4,83 5,335 5,81 6,3 6,77 7,28
D 98 cm 2,62
 3,07 3,53 4,0 4,47 4,93 5,45 5,93 6,43 6,91 7,44
D 99 cm 2,67
 3,135 3,6 4,085 4,56 5,035 5,565 6,06 6,565 7,055 7,585
D 100 cm 2,72
 3,2 3,67 4,17 4,65 5,14 5,68 6,19 6,7 7,2 7,73

How is the cubic capacity of a wooden house calculated during preliminary calculations?

First you need to calculate how many blanks are needed to build a house from a log. IN finished projects from "THE ABC OF THE FOREST" this information contained in the “Cutting Cards” section. The photo below shows summary information for construction by.

This data is for a rounded log with a diameter of 240 mm and a length of 6 meters. We see from the cutting map that for construction we will need 547 blanks, when converted to Cubic Meters according to the table presented above, it turns out to be 146.71 m3. These data are automatically calculated by the AT - WENTS program.

The program in which our architects design wooden houses gives the exact cubic capacity without window and door openings, taking into account all design features wooden house. It is almost impossible to achieve such accuracy with manual calculations.

547*0.33= 180.51 m3.

Thus, we got the result taking into account the lunar groove - the log, relatively speaking, is calculated as a cylinder, and the program calculates minus the lunar groove.

This calculation once again proves the importance professional project and the availability of cutting maps, which allow you to very accurately calculate the amount of logs and lumber and rationally use construction budget. But for approximate calculations to understand the order of prices, this method is very informative.

Mathematical method for calculating the cubic capacity of a wooden house (with a practical example)

What to do if you liked the house in the picture, and you don’t have a complete project, much less a cutting map? In this case, you need to be patient and manually calculate the length of all the logs according to the plan. It must be understood that in this case the error with the real result can be significant, and in both directions.

The task is to calculate how many blanks are needed to build a house from a log. The standard length of a log, as we have previously informed you, often does not exceed 6 meters. It is very important at this stage to determine the height of the floors! And according to this, calculate the number of crowns.

To do this, we need a table of the height of the log profile depending on the diameter. It is presented below. We count the length of all crowns (logs), including pediments, and divide the resulting number by 6.

Round log profile height
Log diameter, mm Crown height, m Crown height, mm
220 0,1905 190,5
240 0,2078 207,8
260 0,2252 225,2
280 0,2425 242,5
300 0,2598
259,8
320 0,2771 277,1
340 0,2944 294,4
360 0,3225 322,5
380 0,3399 339,9
400 0,3572 357,2

EXAMPLE:

Let's assume that we want to build a house from chopped logs with a diameter of 320 mm. One full floor, the second floor is an attic. The desired height of the first floor after shrinkage is 3100 mm, the desired height of the attic near the wall is 1500 mm. The height of one crown with a diameter of 320 mm is 0.2771 mm.

Important! The average height of the first floor of any log house before shrinkage is 3.2 m, the height of the attic wall in the attic is on average 1.5-1.7 m. After shrinkage, the height of the walls will decrease by approximately 7-10%, so this must be taken into account in the initial calculations . It is also necessary to take into account the composition of the floor of the first and second floors. A competent architect will always tell you how to do this correctly.
So, in our example:
  • First floor before shrinkage: 12 crowns, which will be equal to 3.33 m.
  • Attic wall in the attic before shrinkage: 6 crowns, which is equal to 1.66 m.

Now we need the length of the walls of each floor. To do this, it is necessary to calculate the perimeter of all walls (load-bearing and internal) according to the plan.

Let's assume that the length of the first floor is 100 linear meters, and the length attic floor amounted to 85 m.p.This is the result without subtracting window and door openings. If you need a more accurate number, then you need to calculate all openings in length and height and subtract them from the total number.

We will consider a more simplified version of calculating the cubic capacity of a log house from the manufacturer.

So,
  • First floor 100 m*12 crowns = 1200 m.p.
  • Attic floor 85 m * 6 crowns = 510 m.p.
So, the total length of the walls: 1200+510=1710 m.p.

Thus, we received the total length of the walls only, excluding gables, balconies, terraces, vertical support pillars, chopped trusses and other elements that may be included in the house project.

Important! To the resulting cubic capacity result, you need to add 5%, which will be for figured log releases and ridge logs. The exact number depends on the diameter of the log and the cutting method. For approximate calculations, we will limit ourselves to 5%.
So, we divide the resulting length by 6 meters and get 1718 /6 = 286.33 pcs. Thus, to erect walls in our log house, 287 blanks will be required. We multiply this number by 0.59 (data from the “Table for calculating the cubic capacity of round timber”) and get169.33 m3.

We need to add pediments to the resulting cubic capacity. Them in the very simple case 2, they are triangular. The area of ​​2 triangles will be approximately equal to the area of ​​the rectangle. Therefore, we calculate the length of one wall, where the pediment is. We multiply by the number of crowns and get the length of the log in both gables. Divide the result by 6.

Important! The sum of the attic crowns and gables is equal to the height of the first floor. Therefore, if we have 12 crowns on the first floor, and 6 crowns in the attic, then there will be 6 crowns in the gables (12–6=6).
Let's assume that the length of the pediment is 11 meters, we have 6 crowns. This means that 11 * 6 = 66 m. Divide by 6, we get 11 pieces. 11 *0.59 = 6.49 m3

Thus, the cubic capacity of our house made of logs with a diameter of 320 mm is 169.33 + 6.49 = 175.82 m3. When rounded we got 176 m3.

It was possible to go the other way around, first count the number of all blanks, and then convert them into cubic meters. Let's check our result in this way:

287 (blanks for walls) + 11 (blanks for gables) = 298 * 0.59 = 175.82 m3, rounded, 176 m3.

That is, everything was calculated correctly.

Important! Don't forget that this is not the final result yet. You need to study the sketch and if there are terraces, balconies and vertical pillars, they need to be added to total number. We count this manually, because... The calculation you and I have is mathematical. For example, if there are pillars, then each pillar is considered one 6-meter blank of the required diameter. We also consider terrace fencing, cut-overs, chopped trusses and other elements.

Now you know how to calculate the cubic capacity of a log house or a house made of rounded logs. If you DO NOT want to deal with complex calculations yourself, contact our specialists! We will make a detailed estimate for you. This is a free service and does not oblige you to anything.

When ordering a house project made from rounded logs, all lumber will be automatically calculated as accurately as possible.

Ready-made projects of houses and baths from "AZBUKA LESA" are presented in our.

To receive an estimate, send a plan of your future home to

In the letter, indicate the desired diameter of the log, the expected height of each floor, construction technology and other data that the manager needs to know to draw up an accurate estimate.

By mathematical standards, a round timber is a cylinder. The volume of a cylinder is calculated as the area of ​​its circumference multiplied by the length of the cylinder itself (read logs).

where: number Pi- 3,14159265358979; R- radius of the circle; H- the length of the cylinder. But since the comparison of a log with a cylinder is purely conditional, in real calculations the diameter of the log is measured at its midpoint. Naturally, without bark. From school we were taught that the area of ​​a circle is calculated as the number Pi (3.14159) multiplied by the radius of the circle squared. Or another option is, again, the number Pi multiplied by the diameter of the circle to the fourth power. These are purely theoretical calculations of the volume (cubic capacity) of one individual log. What if we are talking about large volumes of timber, the so-called timber stacks, where there are hundreds of cubes of round timber? In this case, of course, no one will calculate m3 of each log. To simplify the work of storekeepers, raters, technologists and other employees of woodworking enterprises, who, as part of their duties, have to deal with wood measurements, they use a round timber cube. This is nothing more than tables approved by GOST, containing calculations of the volume of round timber, depending on the thickness of its top. Experienced loggers and woodworkers poke the timber in increments of 2 cm, usually in even sizes. It is worth noting that specialists who constantly deal with forests can, by eye, with great accuracy, determine the diameter of a log without using rulers or tape measures. And then there are mathematical calculations of the pointing of the forest:

  • there are so many logs of this diameter,
  • so much different diameter
  • and so on.
After that, the volume values ​​of a log of each diameter are taken from the forest cubicle and multiplied by the number linear meters.
For example, a log with a diameter of 20 mm has a volume of 0.23 m3, and there were 100 such logs 6 m long in a stack. Thus, the result is obtained based on the cube size of the lumber: V = 0.23 m3 * 100 pieces = 23 m3 - i.e. the stack will contain 23 m3 with a top diameter of 20 mm.
The volume of logs of other diameters is calculated in a similar way, using the values ​​of a 6-meter-long round timber cube.

Round timber cube table

Part I - the length of the measured timber log ranging from 4 to 8.5 linear meters.
Diameter/cm Length/m

Part II - the length of the measured timber log ranging from 9 to 13.5 linear meters.

Diameter/cm Length/m

Converting warehouse cubic meter of timber to dense

Timber stored in piles in open areas is counted in cubic meters (m3). This is the so-called storage cubic meter forests, measured with all the voids and gaps between the logs.

Essentially, folded m3 is measurements of the stack according to its external dimensions: width, height and length. When implemented, round lumber such a concept as a dense cubic meter of wood is used. What it is? This can be thought of as a stack of timber without voids or any gaps between the logs. That is, like a solid volume of wood. How is the volume of round timber converted into a dense cubic meter? A stack of timber, sorted by length, is measured by its outer dimensions. The values ​​are multiplied and the resulting warehouse m3 is obtained. Next, a special conversion factor is used (see table). As a result of multiplying the resulting volume of folded cubic capacity by the coefficient from the table, the value of the dense forest cube * is obtained.